Precedence of Operators / C language operator precedence / Order of precedence in C language
Now for proceeding to the next lesson of Decision Making Capability of C language, we must have some basic knowledge about theimportance of taking any decision or how importance is it in C language.Decisions are always the most important thing in our lives also, take anyexample from our lives, if someone is roaming in a new place and what he onlyknows is his destination, so when he would read the sign board that theparticular way leads to his desired place he would definitely choose that wayover others. Now relating it to the C language, when we (as a programmer) givechoice to user for more than one paths, then the user have the choice, whichway he wants to choose. The more you give the ease to user for variety ofdecisions the more effective your programming is. It simply asks the user to:
The higher your level of programming, the more complex programming you could to enchance the effectiveness of your programming.
Complex programming is just like complex highways.
Here’s the list of C++ operators according to theirprecedence.
Pre. Operator Description Example Associativity
1 :: Scoping Operator Class::age = 2; none 2 ()
2 () Grouping Operator (a+b)/4;
[ ] Array access array[3]=2;
-> Member access from a pointer ptr->age=20; Left to right
. Member access from an object obj.age=20;
++ Post-increment for( i = 0; i < 10; i++ ) …
— Post-decrement for( i = 0; i < 10; i– ) …
3 ! Logical negation if( !done ) …
~ Bitwise compliment flags = ~flags;
++ Pre-increment for( i = 0; i < 10; ++i ) …
— Pre-decrement for( i = 10; i > 0; –i ) … Right to left
– Unary minus int i = -1;
+ Unary plus int i = +1;
& Address of address = &obj;
(type) Cast to a given type int i = (int) floatNum;
sizeof Return size in bytes int size = sizeof(floatNum);
4 ->* Member pointer selector ptr->*var = 24; Left to right
.* Member object selector obj.*var = 24;
5 * Multiplication int i = 2 * 4;
/ Division float f = 10 / 3; Left to right
% Modulus int rem = 4 % 3;
6 + Addition int a=1+2; Left to right
– Subtraction int s=2-1;
7 << Bitwise shift left int flags = 33 << 1; Left to right
>> Bitwise shift right int flags = 33 >> 1;
8 < Comparison less-than if( i < 42 ) …
<= Comparison less-than-or-equal-to if( i <= 42 ) … Left to right
> Comparison greater-than if( i > 42 ) …
>= Comparison geater-than-or-equal-to if( i >= 42 ) …
9 == Comparison equal-to if( i == 42 ) … Left to right
!= Comparison not-equal-to if( i != 42 ) …
10 & Bitwise AND flags = flags & 42; Left to right
11 ^ Bitwise exclusive OR flags = flags ^ 42; Left to right
12 | Bitwise inclusive (normal) OR flags = flags | 42; Left to right
13 && Logical AND if( conditionA && conditionB ) … Left to right
14 || Logical OR if( conditionA || conditionB ) … Left to right
15 ? : Ternary conditional (if-then-else) int i = (a > b) ? a : b; Right to left
16 = Assignment operator int a = b;
+= Increment and assign a += 3;
-= Decrement and assign b -= 4; Right to left
*= Multiply and assign a *= 5;
/= Divide and assign a /= 2;
%= Bitwise AND and assign a %= 3;
&= Bitwise AND and assign flags &= new_flags;
^= Bitwise exclusive OR and assign flags ^= new_flags;
|= Bitwise inclusive (normal) OR and assign flags |= new_flags;
<<= Bitwise shift left and assign flags <<= 2;
>>= Bitwise shift right and assign flags >>= 2;
17 , Sequential evaluation operator for( i = 0, j = 0; i < 10; i++, j++ ) … Left to right
Regards,
Asjad Azeem.
programmingdoctors 
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